
The graph shows a linear relationship between log |R₀| and time. This suggests a first-order reaction.
In a first-order reaction, the concentration of the reactant decreases exponentially over time. This means:
\[ \ln [R] = \ln [R_0] - kt \]
Taking the logarithm (base 10) of both sides also gives a linear equation, which justifies that a plot of \(\log [R]\) versus time is a straight line.
For a first-order reaction, the slope of the \(\log [R]\) vs time graph is equal to \(-k\), where \(k\) is the rate constant.
So, the slope \(m\) of the graph is:
\[ \text{slope} = -k \]
Consider the following compounds. Arrange these compounds in a n increasing order of reactivity with nitrating mixture. The correct order is : 
