To determine the exceptions to the octet rule, analyze each molecule:
CO$_2$: Follows the octet rule. (C has 8 electrons in its valence shell.
NO$_2$: Exception. It has an odd number of valence electrons (11), making it a free radical.
H$_2$SO$_4$: Follows the octet rule.
BF$_3$: Exception. Boron has only 6 electrons in its valence shell (electron-deficient compound).
CH$_4$: Follows the octet rule.
SiF$_4$: Follows the octet rule.
ClO$_2$: Exception. It is a free radical with an odd number of valence electrons.
PCl$_5$: Exception. Phosphorus has 10 valence electrons (expanded octet).
BeF$_2$:Exception. Beryllium has only 4 valence electrons (electron-deficient compound).
C$_2$H$_6$: Follows the octet rule.
CHCl$_3$: Follows the octet rule.
CBr$_4$: Follows the octet rule.
Molecules that are exceptions to the octet rule:
\[\text{NO}_2, \text{BF}_3, \text{ClO}_2, \text{PCl}_5, \text{BeF}_2\]
Total number of exceptions = 6.
Final Answer:\[6\]
Let $ f(x) = \begin{cases} (1+ax)^{1/x} & , x<0 \\1+b & , x = 0 \\\frac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2} & , x>0 \end{cases} $ be continuous at x = 0. Then $ e^a bc $ is equal to
Total number of nucleophiles from the following is: \(\text{NH}_3, PhSH, (H_3C_2S)_2, H_2C = CH_2, OH−, H_3O+, (CH_3)_2CO, NCH_3\)