To determine the exceptions to the octet rule, analyze each molecule:
CO$_2$: Follows the octet rule. (C has 8 electrons in its valence shell.
NO$_2$: Exception. It has an odd number of valence electrons (11), making it a free radical.
H$_2$SO$_4$: Follows the octet rule.
BF$_3$: Exception. Boron has only 6 electrons in its valence shell (electron-deficient compound).
CH$_4$: Follows the octet rule.
SiF$_4$: Follows the octet rule.
ClO$_2$: Exception. It is a free radical with an odd number of valence electrons.
PCl$_5$: Exception. Phosphorus has 10 valence electrons (expanded octet).
BeF$_2$:Exception. Beryllium has only 4 valence electrons (electron-deficient compound).
C$_2$H$_6$: Follows the octet rule.
CHCl$_3$: Follows the octet rule.
CBr$_4$: Follows the octet rule.
Molecules that are exceptions to the octet rule:
\[\text{NO}_2, \text{BF}_3, \text{ClO}_2, \text{PCl}_5, \text{BeF}_2\]
Total number of exceptions = 6.
Final Answer:\[6\]
Identify the correct orders against the property mentioned:
A. H$_2$O $>$ NH$_3$ $>$ CHCl$_3$ - dipole moment
B. XeF$_4$ $>$ XeO$_3$ $>$ XeF$_2$ - number of lone pairs on central atom
C. O–H $>$ C–H $>$ N–O - bond length
D. N$_2$>O$_2$>H$_2$ - bond enthalpy
Choose the correct answer from the options given below:
Let \( S = \left\{ m \in \mathbb{Z} : A^m + A^m = 3I - A^{-6} \right\} \), where
\[ A = \begin{bmatrix} 2 & -1 \\ 1 & 0 \end{bmatrix} \]Then \( n(S) \) is equal to ______.
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: