Question:

Number of isomeric products formed by monochlorination of 2-methylbutane in presence of sunlight is _______.

Updated On: Mar 21, 2025
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Correct Answer: 6

Solution and Explanation

In the monochlorination of 2-methylbutane, chlorine can replace a hydrogen atom at different positions, leading to the formation of structural and stereoisomeric products. The possible isomeric products are:

CH3CH(Cl)CH2CH(CH3)CH3(±) \text{CH}_3 - \text{CH}(\text{Cl}) - \text{CH}_2 - \text{CH}(\text{CH}_3) - \text{CH}_3 \, (\pm) CH3CH(CH3)CH2CH(Cl)CH3 \text{CH}_3 - \text{CH}(\text{CH}_3) - \text{CH}_2 - \text{CH}(\text{Cl}) - \text{CH}_3 CH3C(Cl)(CH3)CH2CH3(±) \text{CH}_3 - \text{C}(\text{Cl})(\text{CH}_3) - \text{CH}_2 - \text{CH}_3 \, (\pm)

Therefore, there are 6 isomeric products.

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