The Gabriel phthalimide synthesis is used to prepare primary amines (R-NH2). Since the question asks for aromatic amines with the formula C8H11N, we need to consider isomeric primary aromatic amines.
The degree of unsaturation (DU) for C8H11N is:
\( DU = C + 1 - \frac{H - N}{2} = 8 + 1 - \frac{11 - 1}{2} = 9 - 5 = 4 \)
A DU of 4 suggests the presence of a benzene ring (DU = 4). This leaves us with C2H5 to account for. Since the Gabriel synthesis produces primary amines, the nitrogen must be attached to one of these carbons.
The possible isomers are:
Other dimethylanilines (like 3,4-dimethylaniline) are identical to the ones listed above. 2,6-dimethylaniline is the same as 2,3-dimethylaniline.
Therefore, there are 6 possible isomeric aromatic amines that can be synthesized by Gabriel phthalimide synthesis.
At STP \(x\) g of a metal hydrogen carbonate (MHCO$_3$) (molar mass \(84 \, {g/mol}\)) on heating gives CO$_2$, which can completely react with \(0.02 \, {moles}\) of MOH (molar mass \(40 \, {g/mol}\)) to give MHCO$_3$. The value of \(x\) is:
Let one focus of the hyperbola $ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 $ be at $ (\sqrt{10}, 0) $, and the corresponding directrix be $ x = \frac{\sqrt{10}}{2} $. If $ e $ and $ l $ are the eccentricity and the latus rectum respectively, then $ 9(e^2 + l) $ is equal to:
The largest $ n \in \mathbb{N} $ such that $ 3^n $ divides 50! is: