Number of ambidentate ligands in given complex [M(en)(SCN)4]:
Correct Answer: 4
Solution and Explanation
Key Concept:
An ambidentate ligand is a ligand that can coordinate to the central metal atom/ion through two different atoms (donor sites) but only one at a time.
Example: SCN⁻ (Thiocyanate Ion)
- The thiocyanate ion (\( \text{SCN}^- \)) is an ambidentate ligand.
- It can bind to the central atom through:
- Sulfur (S): as a donor atom (soft base).
- Nitrogen (N): as a donor atom (hard base).
Conclusion:
The correct answer is 4, as SCN⁻ is an ambidentate ligand with two donor sites (S and N).
Top Questions on coordination compounds
- Calculate the empirical formula of a compound containing 40% carbon, 6.7% hydrogen, and 53.3% oxygen by mass.
- BITSAT - 2025
- Chemistry
- coordination compounds
- PCl$_3$, 2KCl does not give precipitate of AgCl with AgNO$_3$ solution. Write the structural formula and IUPAC name of the complex.
- CBSE CLASS XII - 2025
- Chemistry
- coordination compounds
- The IUPAC name of complex compound [Co(NH$_3$)$_6$]Cl$_3$ is
- Bihar Board XII - 2025
- Chemistry
- coordination compounds
- Which of the following compounds can be coloured?
- Bihar Board XII - 2025
- Chemistry
- coordination compounds
- Match each complex to its geometry:
- AIIMS Paramedical - 2025
- Chemistry
- coordination compounds
Questions Asked in JEE Main exam
0.01 mole of an organic compound (X) containing 10% hydrogen, on complete combustion, produced 0.9 g H₂O. Molar mass of (X) is ___________g mol\(^{-1}\).
- JEE Main - 2025
- Organic Chemistry
- In the Claisen-Schmidt reaction to prepare dibenzalacetone from 5.3 g benzaldehyde, a total of 3.51 g of product was obtained. The percentage yield in this reaction was _____.
- JEE Main - 2025
- Reaction Mechanisms & Synthesis
- The sum of all local minimum values of the function \( f(x) \) as defined below is:
\[ f(x) = \begin{cases} 1 - 2x & \text{if } x < -1, \\[10pt] \frac{1}{3}(7 + 2|x|) & \text{if } -1 \leq x \leq 2, \\[10pt] \frac{11}{18}(x-4)(x-5) & \text{if } x > 2. \end{cases} \]- JEE Main - 2025
- Functions
- Two balls are selected at random one by one without replacement from a bag containing 4 white and 6 black balls. If the probability that the first selected ball is black, given that the second selected ball is also black, is \(\frac{m}{n}\), where gcd(m, n) = 1, then m + n is equal to:
- JEE Main - 2025
- Probability
If the system of equations \[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \] has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
- JEE Main - 2025
- Matrices and Determinants
Concepts Used:
Coordination Compounds
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
Coordination entity:
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
Ligands:
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.