Question:
Nitrogen has no d-orbital in its valence shell and therefore it cannot1) Exhibits the oxidation state of +52) Have covalency greater than 33) Exhibit orbital Hybridization4) Form oxides with oxidation states greater than +5Select the correct answer using codes given below:
Nitrogen has no d-orbital in its valence shell and therefore it cannot1) Exhibits the oxidation state of +52) Have covalency greater than 33) Exhibit orbital Hybridization4) Form oxides with oxidation states greater than +5Select the correct answer using codes given below:
Updated On: Aug 20, 2024
- (A) 1 only
(B) 2 only
- (C) 1, 2 and 3
- (D) 1 and 4 only
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The Correct Option is B
Solution and Explanation
Explanation:
Nitrogen shows covalency of 4 by coordinate bonding when it donates ns-electron pair to Lewis acid. So, statement 2 is correct.Nitrogen exhibits the oxidation state ranging from -3 in ammonia and +5 in Nitric Acid. So, statement 1 is incorrect.Since Nitrogen has no d-orbitals, it cannot undergo sp3 hybridization. So, statement 3 is incorrect.Nitrogen forms oxides within the range to +5. So, statement 4 is incorrect.Hence, the correct option is (B).
Nitrogen shows covalency of 4 by coordinate bonding when it donates ns-electron pair to Lewis acid. So, statement 2 is correct.Nitrogen exhibits the oxidation state ranging from -3 in ammonia and +5 in Nitric Acid. So, statement 1 is incorrect.Since Nitrogen has no d-orbitals, it cannot undergo sp3 hybridization. So, statement 3 is incorrect.Nitrogen forms oxides within the range to +5. So, statement 4 is incorrect.Hence, the correct option is (B).
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