Question:

Isotherms ($p$-$V$ lines) of one mole of an ideal gas at $T_1$ and $T_2$ have slope ratio 1:2. If $T_1=1000$ K, find $T_2$.

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Slope of $p$-$V$ graph for isotherms $\propto$ temperature. Directly scale slope ratio with $T$.
Updated On: Oct 27, 2025
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The Correct Option is B

Solution and Explanation

• For ideal gas, $pV = nRT \implies \text{slope of $p$ vs $V$ line} \propto T$.
• Slope ratio $T_1:T_2 = 1:2$.
• $T_2 = 2 \times 1000 = 2000$ K.
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