Let the internet handling charges for each ticket be Rs. I and the price of each 3D movie ticket be Rs. X. So, the price of each normal movie ticket= Rs. \(\frac{4}{5}\) X
2 × X + 3 ×\(\frac{4}{5}\)× X + 5 × I = 1030
22 × X + 25 × I = 5150.......... (1)
Also, X + 2 ×\(\frac{4}{5}\) × X + 3 × I = 610
13 × X + 15 × I = 3050........ (2)
Equation (1) X 3 – (2) X 5 gives:
66X + 75I − 65X − 75I = 15450 − 15250
X = 200
So, I = 30
i.e., the internet handling charges for each ticket is Rs. 30.
So, the correct option is (B) : 30.