Question:

$N_2$ and $O_2$ are converted into mono anions, $N_2^{-}$ and $O_2^{-}$ respectively. Which of the following statements is wrong ?

Updated On: Jan 30, 2025
  • In $N_2$, the N?N bond weakens
  • In $O_2$, the O?O bond order increases
  • In $O_2$, bond length decreases
  • $N_2^{-}$ becomes diamagnetic
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The Correct Option is D

Solution and Explanation

In $N_{2}^{-}$ total electrons $=14+1=15$ Electronic configuration of $N_{2}^{-} \sigma 1 s^{2}, \hat{\sigma} 1 s^{2}, \sigma 2 s^{2}, \widehat{\sigma} 2 s^{2}, \sigma 2 p_{x}^{2}, \pi 2 p_{y}^{2} \approx \pi 2 p_{z}^{2}, \star{\pi} 2 p_{z}^{1}$
Due to presence of one unpaired electron, it shows paramagnetic character.
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Concepts Used:

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  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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