\( 2\sqrt{2} < k ≤ 3 \)
\( 2\sqrt{3} < k ≤ 3\sqrt{2} \)
\( 2\sqrt{3} < k <3 \sqrt{3} \)
Given: \(n−1C_r = (k^2 − 8) ^nC_{r+1}\)
We know: \(n−1C_r = (k^2 − 8) ^nC_{r+1}\)
For this expression to hold, \( k^2 − 8 \) must be positive:
\( k^2 − 8 > 0 \Rightarrow k > 2\sqrt{2} \text{ or } k < -2\sqrt{2} \)
Thus, \( k \in (-\infty, -2\sqrt{2}) \cup (2\sqrt{2}, \infty) \)
Next, we check the range \( -3 \le k \le 3 \) to satisfy the constraint. Combining both conditions: \( k \in [2\sqrt{2}, 3] \)
If
$ 2^m 3^n 5^k, \text{ where } m, n, k \in \mathbb{N}, \text{ then } m + n + k \text{ is equal to:} $
Let $ (1 + x + x^2)^{10} = a_0 + a_1 x + a_2 x^2 + ... + a_{20} x^{20} $. If $ (a_1 + a_3 + a_5 + ... + a_{19}) - 11a_2 = 121k $, then k is equal to _______
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)