Question:

Minimum value of \( K \) for which \( x + y + z = K \), \( x<y<z \) does NOT uniquely determine the triplet?

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Try small values manually and look for duplicates.
Updated On: Aug 6, 2025
  • 9
  • 6
  • 7
  • 8
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The Correct Option is D

Solution and Explanation

Try combinations: - For \( K = 6 \): Only one possibility: (1,2,3) - \( K = 7 \): (1,2,4) - \( K = 8 \): (1,2,5), (1,3,4) So for \( K = 8 \), multiple distinct sets possible. \[ \boxed{8} \]
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