A cafeteria offers 5 types of sandwiches. Moreover, for each type of sandwich, a customer can choose one of 4 breads and opt for either small or large sized sandwich. Optionally, the customer may also add up to 2 out of 6 available sauces. The number of different ways in which an order can be placed for a sandwich, is:
Show Hint
When a question says “up to $k$ items” from $n$ options, sum the combinations:
\[
\sum_{r=0}^{k} \binom{n}{r}.
\]
Then multiply by the number of ways for all other independent choices.
We count the number of choices at each step and multiply, since all choices are independent.
Step 1: Choose sandwich type.
There are 5 types:
\[
5 \text{ ways}.
\]
Step 2: Choose bread.
There are 4 breads:
\[
4 \text{ ways}.
\]
Step 3: Choose size.
Small or large:
\[
2 \text{ ways}.
\]
Step 4: Choose sauces (up to 2 out of 6).
The customer may take 0, 1, or 2 sauces (order doesn’t matter):
\[
\binom{6}{0} = 1,\quad
\binom{6}{1} = 6,\quad
\binom{6}{2} = 15.
\]
Total ways to choose sauces:
\[
1 + 6 + 15 = 22.
\]
Step 5: Multiply all choices.
\[
\text{Total ways}
= 5 \times 4 \times 2 \times 22
= 20 \times 44
= 880.
\]
Therefore, the number of different possible sandwich orders is
\[
\boxed{880}.
\]