Question

Match the complexes in list-I with their hybridization in list-II.

• A. I-C, II-D, III-A, IV-B
• B. I-D, II-C, III-A, IV-B
• C. I-D, II-C, III-B, IV-A
• D. I-C, II-D, III-B, IV-A

Hint:

For octahedral and square planar complexes, remember the typical hybridization (d\(^2\)sp\(^3\) or dsp\(^2\)), and for tetrahedral complexes, it's typically sp\(^3\).

Answer 1

The Correct Option is C

The hybridization of the complexes can be determined by the number of ligands and their geometry. Here are the correct matches:
- Ni(CO)\(_4\): The complex is tetrahedral, hence sp\(^3\).
- [Ni(CN)\(_4\)]\(^{2-}\): The complex is square planar, requiring dsp\(^2\) hybridization.
- [Co(NH\(_3\))\(_6\)]\(^{3+}\): The complex is octahedral, so the hybridization is d\(^2\)sp\(^3\).
- [CoF\(_6\)]\(^{3-}\): The complex is octahedral, so sp\(^3\) hybridization.