| List-I (Compound) | List-II (Colour) |
|---|---|
| (A) \(Fe_4[Fe(CN)_6]_3.xH_2O\) | (I) Violet |
| (B) \( [Fe(CN)_5NOS]^{4–} \) | (II) Blood Red |
| (C) \( [Fe(SCN)]^{2+}\) | (III) Prussian Blue |
| (D) \((NH_4)_3PO_4.12MoO_3\) | (IV) Yellow |
To solve this chemistry question, we need to match each compound from List-I with its corresponding color from List-II. Let's analyze each compound:
Based on the above analysis, the correct matching of compounds to their colors is A-III, B-I, C-II, D-IV. This matches with the provided correct answer.
To solve this matching problem, we need to correctly associate each compound in List-I with its corresponding color in List-II. Let us consider each compound one by one:
Based on this analysis, the correct matching of each compound with its respective color is:
The correct answer is: A-III, B-I, C-II, D-IV.
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.
Consider the following two reactions A and B: 
The numerical value of [molar mass of $x$ + molar mass of $y$] is ___.