Match List-I with List-IIList-I
(Compound) List-II
(Colour) (A) \(Fe_4[Fe(CN)_6]_3.xH_2O\) (I) Violet (B) \( [Fe(CN)_5NOS]^{4–} \) (II) Blood Red (C) \( [Fe(SCN)]^{2+}\) (III) Prussian Blue (D) \((NH_4)_3PO_4.12MoO_3\) (IV) Yellow
Choose the correct answer from the options given below:
| List-I (Compound) | List-II (Colour) |
|---|---|
| (A) \(Fe_4[Fe(CN)_6]_3.xH_2O\) | (I) Violet |
| (B) \( [Fe(CN)_5NOS]^{4–} \) | (II) Blood Red |
| (C) \( [Fe(SCN)]^{2+}\) | (III) Prussian Blue |
| (D) \((NH_4)_3PO_4.12MoO_3\) | (IV) Yellow |
Choose the correct answer from the options given below:
- A-III, B-I, C-II, D-IV
- A-IV, B-I, C-II, D-III
- A-II, B-III, C-IV, D-I
- A-I, B-II, C-III, D-IV
The Correct Option is A
Solution and Explanation
Matching Explanation :
Fe$_4$[Fe(CN)$_6$]$_3$ $\cdot$ $x$H$_2$O: Prussian Blue (Colour: III)
[Fe(CN)$_5$NOS]$^{4-}$: Violet (Colour: I)
[Fe(SCN)]$^{2+}$: Blood Red (Colour: II)
(NH$_4$)$_3$PO$_4$ $\cdot$ 12MoO$_3$: Yellow (Colour: IV)
A-III, B-I, C-II, D-IV
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