
To solve this matching question, we need to identify the common uses of each compound listed in List-I by matching them correctly with List-II.
Based on the analysis, the correct match of List-I with List-II is:
Therefore, the correct answer is: (A)-(III), (B)-(I), (C)-(IV), (D)-(II).
Matching Explanation: -
(A) Carbon tetrachloride: Used as a fire extinguisher in the past due to its non-flammable properties. Hence, it matches with (III).
(B) Methylene chloride: Commonly used as a paint remover due to its ability to dissolve paint and coatings. Hence, it matches with (I).
(C) DDT: Known for its use as a non-biodegradable insecticide, which has been widely restricted due to environmental concerns. Hence, it matches with (IV).
(D) Freons: These are used as refrigerants and in air conditioners due to their heat absorption and transfer properties. Hence, it matches with (II).
Conclusion: The correct matching is:
• (A)-(III)
• (B)-(I)
• (C)-(IV)
• (D)-(II)
Match List - I with List - II:
List - I:
(A) \([ \text{MnBr}_4]^{2-}\)
(B) \([ \text{FeF}_6]^{3-}\)
(C) \([ \text{Co(C}_2\text{O}_4)_3]^{3-}\)
(D) \([ \text{Ni(CO)}_4]\)
List - II:
(I) d²sp³ diamagnetic
(II) sp²d² paramagnetic
(III) sp³ diamagnetic
(IV) sp³ paramagnetic
Consider the following sequence of reactions : 
Molar mass of the product formed (A) is ______ g mol\(^{-1}\).

In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by: