| List I (Substances) | List II (Element Present) |
| (A) Ziegler catalyst | (I) Rhodium |
| (B) Blood Pigment | (II) Cobalt |
| (C) Wilkinson catalyst | (III) Iron |
| (D) Vitamin B12 | (IV) Titanium |
The question requires us to match substances with the elements present in them. Let's analyze each pair:
Thus, the correct combination is:
| List I (Substances) | List II (Element Present) |
| (A) Ziegler catalyst | (IV) Titanium |
| (B) Blood Pigment | (III) Iron |
| (C) Wilkinson catalyst | (I) Rhodium |
| (D) Vitamin B12 | (II) Cobalt |
Therefore, the correct answer is: A-IV, B-III, C-I, D-II
Ziegler catalyst → Titanium
Blood pigment (hemoglobin) → Iron
Wilkinson catalyst → Rhodium
Vitamin B12 → Cobalt
Thus, the correct matching is:
A-IV, B-III, C-I, D-II
So, the correct answer is: Option (4)
Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.