Question:

Based on Valence Bond Theory, explain the geometry and magnetic character of [NiCl$_4$]$^{2-$. [Atomic number: Ni = 28]}

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In tetrahedral complexes, the metal ion undergoes sp$^3$ hybridization, leading to specific geometry and magnetic properties.
Updated On: Jul 11, 2025
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Solution and Explanation

According to Valence Bond (VB) Theory, the geometry and magnetic properties of the complex depend on the hybridization and the number of unpaired electrons in the central metal ion. In [NiCl$_4$]$^{2-}$, Ni$^{2+}$ has the electron configuration 3d$^8$4s$^0$. The central Ni$^{2+}$ ion undergoes sp$^3$ hybridization with four chloride ions, forming a tetrahedral geometry. Since all electrons are paired in the d-orbitals of Ni$^{2+}$, [NiCl$_4$]$^{2-}$ is diamagnetic.
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