List-I (Processes/ Reactions) | List-II (Catalyst) |
---|---|
(A) \(2SO_2(g) + O_2(g)\) | (I) \(\underrightarrow {Fe(s)}\ \ 2SO_3(g)\) |
(B) \(4NH_3(g) + 5O_2(g)\) | (II) \(\underrightarrow {Pt(s) – Rh(s)}\ \ 4NO(g) + 6H_2O(g)\) |
(C) \(N_2(g) + 3H_2(g)\) | (III) \(\underrightarrow {V_2O_5}\ \ 2NH_3(g)\) |
(D) Vegetable oil \((l)+ H_2\) | (IV) \(\underrightarrow {Ni(s)}\) Vegetable ghee(s) |
(A) \(2SO_2(g) + O_2(g) \xrightarrow{V_2O_5}2SO_3\)
(B) \(4NH_3(g) + 5O_2(g)\xrightarrow{Pt(s)-Rh(s)}4NO(g)+6H_2O(g)\)
(C) \(N_2(g) + 3H_2(g) \xrightarrow{Fe(s)}2NH_3(g)\)
(D) Vegetable oil (l) \(+ H_2 \xrightarrow{Ni(s)}\) Vegetable ghee(s)
So, the correct option is (B): (A)-(III), (B)-(II), (C)-(I), (D)-(IV).
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
In the given circuit the sliding contact is pulled outwards such that the electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 Ω, the value of the current in the circuit will be A.
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.