List I (Mixture) | List II (Separation Technique) | ||
A | CHCl3+C6H5NH2 | i | Steam distillation |
B | C6H14+C5H12 | ii | Differential extraction |
C | C6H5NH2+H2O | iii | Distillation |
D | Organic compound in H2O | iv | Fractional distillation |
(A) CHCl$_3$ + C$_6$H$_5$NH$_2$: The mixture consists of chloroform and aniline, which can be separated by distillation.
(B) C$_6$H$_14$ + C$_5$H$_12$: The mixture consists of alkanes, which can be separated by fractional distillation.
(C) C$_6$H$_5$NH$_2$ + H$_2$O: Aniline and water can be separated by steam distillation.
(D) Organic compound in H$_2$O: This mixture can be separated by differential extraction.
Thus, the correct answer is: \[ \text{(2) A-I, B-II, C-III, D-IV.} \]
Given below are two statements:
Statement I: D-(+)-glucose + D-(+)-fructose $\xrightarrow{H_2O}$ sucrose sucrose $\xrightarrow{\text{Hydrolysis}}$ D-(+)-glucose + D-(+)-fructose
Statement II: Invert sugar is formed during sucrose hydrolysis.
In the light of the above statements, choose the correct answer from the options given below -
Match the following:
Match List-I with List-II.
Choose the correct answer from the options given below :
The scientific study of matter’s properties and behaviour is known as chemistry. It is a natural science that studies the elements that makeup matter, as well as the compounds, made up of atoms, molecules, and ions: their composition, structure, qualities, and behaviour, as well as the changes that occur when they mix with other things.