Question:

Match List-I with List-II :
List - I(Block/group in periodic table)List - II(Element)
(A) Lanthanoid(I) Ce
(B) d-block element(II) As
(C) p-block element(III) Cs
(D) s-block element (IV) Mn
Identify the correct answer from the options given below :

Updated On: Dec 9, 2024
  • A-I, B-II, C-IV, D-III
  • A-I, B-IV, C-III, D-II
  • A-I, B-IV, C-II, D-III
  • A-IV, B-I, C-II, D-III
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Based on their positions in the periodic table:

  • Cerium (Ce) is a lanthanoid element. Thus A-I.
  • Manganese (Mn) is a d-block element. Thus B-IV.
  • Arsenic (As) is a p-block element. Thus C-II.
  • Cesium (Cs) is an s-block element. Thus D-III.

Therefore, the correct answer is (3): A-I, B-IV, C-II, D-III.

Was this answer helpful?
0
0