Question

Match List-I with List-II for the following reaction pattern: \[ \text{Glucose} \quad \text{Reagent} \quad \rightarrow \quad \text{Product} \quad \rightarrow \quad \text{Structural prediction} \] 

 

• A. a-iii, b-i, c-ii, d-iv
• B. a-i, b-ii, c-iii, d-iv
• C. a-iii, b-ii, c-i, d-iv
• D. a-iv, b-iii, c-ii, d-i

Hint:

When working with glucose reactions, it is essential to recognize the functional group that each reagent will interact with, such as the aldehyde, hydroxyl, or carbonyl group.

Answer 1

The Correct Option is A

- When glucose reacts with acetic anhydride, it results in an esterification reaction, where glucose forms an ester with the anhydride, producing a product that has a straight chain of six carbon atoms (prediction ii). Hence, a-i is incorrect. 
- When glucose reacts with bromine water, it leads to oxidation of the aldehyde group in glucose. The resulting product has an aldehyde group, which corresponds to prediction i. Hence, b-i is correct. 
- Hydroiodic acid reaction with glucose results in the replacement of the hydroxyl groups by iodine, giving the product with five hydroxyl groups, which matches prediction iii. Hence, c-ii is correct. 
- Hydrogen cyanide reacts with glucose, resulting in the formation of a cyano group, which corresponds to prediction iv (a carbonyl group). Hence, d-iv is correct. 

Thus, the correct match is: \[ \text{(1) } a-iii, b-i, c-ii, d-iv \]