Question:

Match List - I with List - II: 

Structure & IUPAC Name  (A) C6H{13}CH=CH2 & (I) 4 - Methylpent-1-ene  (B) (CH3)2C(C5H3) & (II) 4, 4

Choose the correct answer from the given below options

Show Hint

When naming organic compounds, identify the longest carbon chain, number the chain, and locate the substituents correctly to assign the correct IUPAC name.
Updated On: Nov 2, 2025
  • (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
  • (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
  • (A)-(I), (B)-(III), (C)-(II), (D)-(IV)
  • (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Approach Solution - 1

- Structure (A) corresponds to a molecule with a methyl group attached to a pentene, and the correct IUPAC name is 4-methylpent-1-ene, so (A)-(I). 
- Structure (B) is a dimethyl-substituted heptane, and the correct IUPAC name is 4, 4-dimethylheptane, so (B)-(III). 
- Structure (C) is a compound with an ethyl group and a methyl group attached to a heptane chain, and the correct name is 3-ethyl-5-methylheptane, so (C)-(II). 
- Structure (D) is a compound with a methyl group and a pentadiene chain, and the correct name is 2-methyl-1,3-pentadiene, so (D)-(IV). 
Thus, the correct matching is (A)-(I), (B)-(III), (C)-(II), (D)-(IV).

Was this answer helpful?
0
0
Hide Solution
collegedunia
Verified By Collegedunia

Approach Solution -2

Step 1: Understand the question.
We are given a list of hydrocarbon structures (List - I) and a list of corresponding IUPAC names (List - II). We need to correctly match each structure with its IUPAC name based on the rules of nomenclature.

List - I (Structures):
(A) C₆H₁₃CH = CH₂
(B) (CH₃)₂C(C₂H₅)₂
(C) CH₃CH₂C(CH₃)CH₂
(D) CH₂CH₂C(CH₃)C = CH₂

List - II (IUPAC Names):
(I) 4-Methylpent-1-ene
(II) 4,4-Dimethylheptane
(III) 3-Ethyl-5-methylheptane
(IV) 2-Methyl-1,3-pentadiene

Step 2: Identify and name each structure.
- (A) C₆H₁₃CH = CH₂:
This compound has a double bond at the end and a methyl group attached to the fourth carbon of a pentene chain.
Thus, it is named 4-Methylpent-1-ene. → (I)

- (B) (CH₃)₂C(C₂H₅)₂:
This structure represents a heptane derivative with two methyl groups on the fourth carbon atom.
Thus, it is named 4,4-Dimethylheptane. → (II)

- (C) CH₃CH₂C(CH₃)CH₂:
This corresponds to a branched heptane structure containing both an ethyl and a methyl substituent at positions 3 and 5 respectively.
Thus, it is named 3-Ethyl-5-methylheptane. → (III)

- (D) CH₂CH₂C(CH₃)C = CH₂:
This compound contains two double bonds (a diene) with a methyl substituent on the second carbon.
Thus, it is named 2-Methyl-1,3-pentadiene. → (IV)

Step 3: Final matching.
(A) → (I) 4-Methylpent-1-ene
(B) → (III) 3-Ethyl-5-methylheptane
(C) → (II) 4,4-Dimethylheptane
(D) → (IV) 2-Methyl-1,3-pentadiene

Final Answer:
\[ \boxed{(A)-(I), (B)-(III), (C)-(II), (D)-(IV)} \]
Was this answer helpful?
0
0