Question

Match List - I with List - II according to shape. List - I A. XeO\(_3\) B. XeF\(_2\) C. XeO\(_2\)F\(_2\) D. XeOF\(_4\) List - II I. BrF\(_5\) II. NH\(_3\) III. [I\(_3\)]\(^{-}\) IV. SF\(_4\) Choose the correct answer from the options given below:

• A. A-II, B-III, C-I, D-IV
• B. A-II, B-I, C-III, D-IV
• C. A-II, B-III, C-IV, D-I
• D. A-III, B-II, C-IV, D-I

Hint:

For xenon compounds, use VSEPR theory: - Count bonding pairs and lone pairs. - Match with known reference molecules (NH\(_3\), [I\(_3\)]\(^{-}\), BrF\(_5\), SF\(_4\)).

Answer 1

The Correct Option is A

Step 1: Analyze XeO\(_3\). - Central atom Xe has 3 double bonds with O and one lone pair. - Shape: trigonal pyramidal (similar to NH\(_3\)). \[ \text{A → II} \]
Step 2: Analyze XeF\(_2\). - Central atom Xe has 2 bonding pairs and 3 lone pairs. - Shape: linear (similar to [I\(_3\)]\(^{-}\)). \[ \text{B → III} \]
Step 3: Analyze XeO\(_2\)F\(_2\). - Central atom Xe has 4 bonding pairs and 1 lone pair. - Shape: square pyramidal (similar to BrF\(_5\)). \[ \text{C → I} \]
Step 4: Analyze XeOF\(_4\). - Central atom Xe has 5 bonding pairs and 1 lone pair. - Shape: distorted octahedral (square pyramidal-like, similar to SF\(_4\)). \[ \text{D → IV} \] Final Matching: \[ A \to II, \quad B \to III, \quad C \to I, \quad D \to IV \]