Question:

Identify the CORRECT set of details from the following:
A. $[\text{Co}(\text{NH}_3)_6]^{3+$: Inner orbital complex; $d^2sp^3$ hybridized
B. $[\text{MnCl}_6]^{3-}$: Outer orbital complex; $sp^3d^2$ hybridized
C. $[\text{CoF}_6]^{3-}$: Outer orbital complex; $d^2sp^3$ hybridized
D. $[\text{FeF}_6]^{3-}$: Outer orbital complex; $sp^3d^2$ hybridized
E. $[\text{Ni}(\text{CN})_4]^{2-}$: Inner orbital complex; $sp^3$ hybridized}

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Hybridization types: $d^2sp^3$ (Inner Octahedral), $sp^3d^2$ (Outer Octahedral), $dsp^2$ (Square Planar), $sp^3$ (Tetrahedral).
Updated On: Feb 5, 2026
  • A, B, C, D & E
  • C & D Only
  • A, B & D Only
  • A, C & E Only
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The Correct Option is C

Solution and Explanation

A. $\text{Co}^{3+} (d^6)$, $\text{NH}_3$ is strong field. Low spin, inner orbital $d^2sp^3$. Correct.
B. $\text{Mn}^{3+} (d^4)$, $\text{Cl}^-$ is weak field. High spin, octahedral $sp^3d^2$. Correct.
C. $\text{Co}^{3+} (d^6)$, $\text{F}^-$ is weak field. High spin, octahedral $sp^3d^2$. Hybridization $d^2sp^3$ is incorrect here.
D. $\text{Fe}^{3+} (d^5)$, $\text{F}^-$ is weak field. High spin, octahedral $sp^3d^2$. Correct.
E. $\text{Ni}^{2+} (d^8)$, $\text{CN}^-$ is strong field. Low spin, square planar $dsp^2$. Hybridization $sp^3$ is incorrect.
Correct details are A, B, and D.
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