\(R = R_0A^{\frac{1}{3}}\)
\(⇒ \frac{R_1}{R_2} = \bigg(\frac{A_1}{A_2}\bigg)^\frac{1}{3}\)
\(= \bigg(\frac{4}{3}\bigg)^{\frac{1}{3}}\)
Ratio of density between two nuclei: \(\frac{ρ_1}{ρ_2} = \frac{\frac{A_1}{V_1}}{\frac{A_2}{V_2}}\)
= \(\bigg(\frac{A_1}{A_2}\bigg) \times \bigg(\frac{R_2}{R_1}\bigg)^3\)
= \(1 : 1\)
A bob of mass \(m\) is suspended at a point \(O\) by a light string of length \(l\) and left to perform vertical motion (circular) as shown in the figure. Initially, by applying horizontal velocity \(v_0\) at the point ‘A’, the string becomes slack when the bob reaches at the point ‘D’. The ratio of the kinetic energy of the bob at the points B and C is:
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.
Read More: Nuclei