Refractive index of a medium nm is given by,
\(n_m = \frac{\text{Speed of light in vacuum}}{\text{Speed of light in the medium }}\)
\(=\frac{ c }{v}\)
Speed of light in vacuum, c = 3 × 108 m s−1
Refractive index of glass, ng = 1.50
Speed of light in the glass,
\(v=\frac{c}{n_g}\)
\(=\frac{3\times10^8}{1.50}\)
\(=2\times10^8\) ms-1
Two light beams fall on a transparent material block at point 1 and 2 with angle \( \theta_1 \) and \( \theta_2 \), respectively, as shown in the figure. After refraction, the beams intersect at point 3 which is exactly on the interface at the other end of the block. Given: the distance between 1 and 2, \( d = 4/3 \) cm and \( \theta_1 = \theta_2 = \cos^{-1} \frac{n_2}{2n_1} \), where \( n_2 \) is the refractive index of the block and \( n_1 \) is the refractive index of the outside medium, then the thickness of the block is cm. 
(i) Study the diagram and name the parts marked as A, B, C, and D.
(ii) Write the function of A and C.