Question

Let y = y(x), y>0, be a solution curve of the differential equation (1 + x²) dy=y (x–y)dx. If y(0)=1 and y(2√2) , = b then

• A. \(e β^{ − 1} = e^{-2} ( 3 + 2 √ 2 )\)
• B. \(e ^3 β^{ − 1} = e ( 3 + 2 √ 2 )\)
• C. \(e β^{ − 1} = e^{-2} ( 5+ √ 2 )\)
• D. \(e3 β^{ − 1} = e^{-2} ( 3+ 2√ 2 )\)

Answer 1

The Correct Option is D

The correct option is(D): \(e3 β^{ − 1} = e^{-2} ( 3+ 2√ 2 )\)