Question:
Let the line \( \frac{x^2}{2} - \frac{y^2}{1} = 1 \) lie in the plane \( x + 3y - oz + \beta = 0 \). Then \( \beta \) equals:
Let the line \( \frac{x^2}{2} - \frac{y^2}{1} = 1 \) lie in the plane \( x + 3y - oz + \beta = 0 \). Then \( \beta \) equals:
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The equation of a plane with a line intersection can be solved using geometrical methods, such as projecting the line onto the plane.
Updated On: Jan 12, 2026
- \( (6, 7) \)
- \( (6, 7) \)
- \( (-6, 7) \)
- \( (6, 15) \)
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The Correct Option is A
Solution and Explanation
Step 1: Identify the general equation of the line in the plane and use the geometric properties to find the value of \( \beta \).
Step 2: Substitute into the plane equation to solve for \( \beta \) and determine the correct values.
Final Answer: \[ \boxed{(6, 7)} \]
Step 2: Substitute into the plane equation to solve for \( \beta \) and determine the correct values.
Final Answer: \[ \boxed{(6, 7)} \]
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