The graph below depicts both expressions.
The desired area is equal to 4 times the area of the red triangle.
The area of the red triangle is calculated using the formula: \[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \] Given the values, we compute: \[ \text{Area} = \frac{1}{2} \times 1 \times 1 = \frac{1}{2} \text{ square units} \]
Therefore, the required area is: \[ 4 \times \frac{1}{2} = 2 \text{ square units} \]
Final Answer: \( \boxed{2} \) square units
ABCD is a trapezoid where BC is parallel to AD and perpendicular to AB . Kindly note that BC<AD . P is a point on AD such that CPD is an equilateral triangle. Q is a point on BC such that AQ is parallel to PC . If the area of the triangle CPD is 4√3. Find the area of the triangle ABQ.