Area of the triangle = 1/2 |x1(y2-y3) + x2(y3-y1) + x3(y1-y2)|
Area of the triangle = 1/2 |a((b+4c)-3c) + a(3c-(b-2c)) + 2a(b-2c)-(b+4c))|
Area of the triangle = 1/2 |a(b+c) + a(5c-b) - 2a(-6c)|
Area of the triangle = 1/2 |ab + ac + 5ac - ab + 12ac| = 1/2 |18ac| = 9ac
Hence, option D is the correct answer.
ABCD is a trapezoid where BC is parallel to AD and perpendicular to AB . Kindly note that BC<AD . P is a point on AD such that CPD is an equilateral triangle. Q is a point on BC such that AQ is parallel to PC . If the area of the triangle CPD is 4√3. Find the area of the triangle ABQ.