Step 1: Formula for the area of a triangle using coordinates:
\[ \text{Area} = \tfrac{1}{2} \Big| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \Big| \]
Step 2: Substitute the given points into the formula.
\[ \text{Area} = \tfrac{1}{2} \Big| a\big((b+4c) - 3c\big) \;+\; a\big(3c - (b - 2c)\big) \;+\; 2a\big((b - 2c) - (b + 4c)\big) \Big| \]
Step 3: Simplify each term.
\[ = \tfrac{1}{2} \Big| a(b + c) \;+\; a(5c - b) \;-\; 2a(-6c) \Big| \]
Step 4: Expand further.
\[ = \tfrac{1}{2} \Big| ab + ac + 5ac - ab + 12ac \Big| \]
Step 5: Combine like terms.
\[ = \tfrac{1}{2} \Big| 18ac \Big| \]
Step 6: Final area of the triangle.
\[ \text{Area} = 9ac \]
\[ \boxed{9ac} \]
Option D
ABCD is a trapezoid where BC is parallel to AD and perpendicular to AB . Kindly note that BC<AD . P is a point on AD such that CPD is an equilateral triangle. Q is a point on BC such that AQ is parallel to PC . If the area of the triangle CPD is 4√3. Find the area of the triangle ABQ.