ABCD is a trapezoid where BC is parallel to AD and perpendicular to AB . Kindly note that BC<AD . P is a point on AD such that CPD is an equilateral triangle. Q is a point on BC such that AQ is parallel to PC . If the area of the triangle CPD is 4√3. Find the area of the triangle ABQ.
According to the question:
AQ = PC, AB = CR, ABQ ≃ CRP
Then, Area of ABQ = Area of CRP = 1/2 x Area of CPD = 1/2 x 4√3 = 2√3
Hence, option A is the correct answer.