Let \( \overrightarrow{a} = i + 2j + k \) and \( \overrightarrow{b} = 2i + 7j + 3k \).
Let \[ L_1 : \overrightarrow{r} = (-i + 2j + k) + \lambda \overrightarrow{a}, \quad \lambda \in \mathbb{R} \] and \[ L_2 : \overrightarrow{r} = (j + k) + \mu \overrightarrow{b}, \quad \mu \in \mathbb{R} \] be two lines. If the line \( L_3 \) passes through the point of intersection of \( L_1 \) and \( L_2 \), and is parallel to \( \overrightarrow{a} + \overrightarrow{b} \), then \( L_3 \) passes through the point:
Step 1: The parametric equations of the lines \( L_1 \) and \( L_2 \) are given, and the line \( L_3 \) passes through their point of intersection and is parallel to \( \overrightarrow{a} + \overrightarrow{b} \).
Step 2: To find the point of intersection, we need to solve the system of equations given by the parametric equations of \( L_1 \) and \( L_2 \). After solving this, we obtain the coordinates of the intersection point.
Step 3: Since \( L_3 \) is parallel to \( \overrightarrow{a} + \overrightarrow{b} \), we use this direction vector and the intersection point to identify the correct coordinates that satisfy the condition. Thus, the correct answer is (A).
Let \( ABC \) be a triangle formed by the lines \( 7x - 6y + 3 = 0 \), \( x + 2y - 31 = 0 \), and \( 9x - 2y - 19 = 0 \).
Let the point \( (h, k) \) be the image of the centroid of \( \triangle ABC \) in the line \( 3x + 6y - 53 = 0 \). Then \( h^2 + k^2 + hk \) is equal to: