Given the function f(x) with the following conditions:
We need to determine the value of \(f(f(f(a)))=21.\)
First, let's break it down step by step:
Now, we solve for a such that \(f(f(f(a)))=21.\)
Thus, the only solution that works is for a=12.
Now, let's compute the limit:
\(\lim_{x \to 12} f(x) = f(12) = 2 \times 12 = 24\)
So, the correct answer is 144.
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $
Resonance in X$_2$Y can be represented as
The enthalpy of formation of X$_2$Y is 80 kJ mol$^{-1}$, and the magnitude of resonance energy of X$_2$Y is: