Question:

Let $f : R \to R$ be a function defined by $f(x) = \frac{x -m}{x-n}$ , where $m \neq n$, then

Updated On: Jun 23, 2023
  • f is one-one onto
  • f is one-one into
  • f is many-one onto
  • f is many-one into
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The Correct Option is B

Solution and Explanation

Let $f : R \to R$ be a function defined by $f(x) = \frac{x -m}{x-n}$ For any $ (x, y) \in R$ Let $f (x) = f (y)$ $\Rightarrow \frac{x-m}{x-n} = \frac{y-m}{y-n} \Rightarrow x =y $ $ \therefore f$ is one - one Let $\alpha \in R $ such that $ f\left(x\right) = \alpha $ $ \Rightarrow \alpha = \frac{x-m}{x-n} \Rightarrow \left(x-n\right)\alpha = x-m$ $ \Rightarrow x \alpha-n \alpha=x -m $ $ \Rightarrow x\alpha-x =n\alpha-m$ $ \Rightarrow x\left(\alpha-1\right)=n\alpha-m$ $ \Rightarrow x = \frac{n\alpha-m}{\alpha-1} $ for $\alpha=1 , x \notin R $ So, $f$ is not onto.
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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions