\(f(x)=(2(1−\frac {x^{25}}{2})(2+x^{25}))^{\frac {1}{50}}\)
\(f(x)=(2(\frac {2−x^{25}}{{2}})(2+x^{25}))^{\frac {1}{50}}\)
\(=(4−x^{50})^{\frac {1}{50}}\)
\(f(f(x))=(4−((4−x^{50})^{\frac {1}{50}})^{50})^{\frac {1}{50}}=x\)
As \(f(f(x)) = x\) we have
\(g(x) = f(f(f(x))) + f(f(x)) = f(x) + x\)
\(g(x) = (4 – x^{50})^{\frac {1}{50}} + x\)
\(g(1) = 3^{\frac {1}{50}} + 1\)
\([g(1)] = 2\)
So, the answer is \(2\).
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
A relation R from a non-empty set B is a subset of the cartesian product A × B. The subset is derived by describing a relationship between the first element and the second element of the ordered pairs in A × B.
A relation f from a set A to a set B is said to be a function if every element of set A has one and only one image in set B. In other words, no two distinct elements of B have the same pre-image.
Relations and functions can be represented in different forms such as arrow representation, algebraic form, set-builder form, graphically, roster form, and tabular form. Define a function f: A = {1, 2, 3} → B = {1, 4, 9} such that f(1) = 1, f(2) = 4, f(3) = 9. Now, represent this function in different forms.