Question:

Let f be a differential function satisfying
f(x) =\(\frac{ 2}{√3} \)\(∫^{√30} f(\frac{λ2x}{3})dλ,x>0 and f(1) = √3.\)
If y = f(x) passes through the point (α, 6), then α is equal to _____

Updated On: Mar 2, 2024
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Correct Answer: 12

Solution and Explanation

∵ f(x) = \(\frac{2}{√3} \)\(∫^{√3}_0 f(\frac{λ^2x}{3})dλ, x>0....(i)\)
On differentiating both sides w.r.t., x, we get

f'(x) =\(\frac{2}{√3} \)\(∫^{√3}_0\)\(\frac{λ^2}{3}f'( \frac{λ^2x}{3})dλ\)
f'(x) = \(\frac{1}{√3} \)\(∫^{√3}_0\) λ. \(\frac{λ^2}{3}f'( \frac{λ^2x}{3})dλ\)
\(xf'(x) =\frac{ f(x)}{2}\)
On integrating we get :
In y = \(\frac{1}{2} \)In x + In c
∵ f(1) = √3 then c = √3
∴ (α,6) lies on
∴ y = √3x
∴ 6 = √3α
⇒ α = 12

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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions