Let the equations of the lines be:
For Line 1:
\[ \frac{x + 6}{3} = \frac{y}{2} = \frac{z + 1}{1} = \lambda \] Then \(x = 3\lambda - 6\), \(y = 2\lambda\), \(z = \lambda - 1\).
For Line 2:
\[ \frac{x - 7}{4} = \frac{y - 9}{3} = \frac{z - 4}{2} = \mu \] Then \(x = 4\mu + 7\), \(y = 3\mu + 9\), \(z = 2\mu + 4\).
By equating the coordinates, we get the system of equations:
\[ \begin{aligned} 3\lambda - 6 &= 4\mu + 7 \quad (1) \\ 2\lambda &= 3\mu + 9 \quad (2) \\ \lambda - 1 &= 2\mu + 4 \quad (3) \end{aligned} \] Solving these equations, we find the values of \(\lambda\) and \(\mu\) at the point of intersection as \(\lambda = 3\) and \(\mu = -1\). Thus, the intersection point is \((3, 6, 2)\).
The distance \(d\) from the point \((7, 8, 9)\) to \((3, 6, 2)\) is:
\[ d = \sqrt{(7 - 3)^2 + (8 - 6)^2 + (9 - 2)^2} = \sqrt{16 + 4 + 49} = \sqrt{69} \] Therefore,
\[ d^2 + 6 = 69 + 6 = 75 \]
The equivalent resistance between the points \(A\) and \(B\) in the given circuit is \[ \frac{x}{5}\,\Omega. \] Find the value of \(x\). 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.