Question:

Let \( d \) be the distance of the point of intersection of the lines \(\frac{x+6}{3} = \frac{y}{2} = \frac{z+1}{1}\) and \(\frac{x-7}{4} = \frac{y-9}{3} = \frac{z-4}{2}\) from the point \((7, 8, 9)\). Then \( d^2 + 6 \) is equal to:

Updated On: Nov 6, 2025
  • 72
  • 69
  • 75
  • 78
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Approach Solution - 1

Let the equations of the lines be: 
For Line 1: 
\[ \frac{x + 6}{3} = \frac{y}{2} = \frac{z + 1}{1} = \lambda \] Then \(x = 3\lambda - 6\), \(y = 2\lambda\), \(z = \lambda - 1\). 
For Line 2: 
\[ \frac{x - 7}{4} = \frac{y - 9}{3} = \frac{z - 4}{2} = \mu \] Then \(x = 4\mu + 7\), \(y = 3\mu + 9\), \(z = 2\mu + 4\). 
By equating the coordinates, we get the system of equations: 
\[ \begin{aligned} 3\lambda - 6 &= 4\mu + 7 \quad (1) \\ 2\lambda &= 3\mu + 9 \quad (2) \\ \lambda - 1 &= 2\mu + 4 \quad (3) \end{aligned} \] Solving these equations, we find the values of \(\lambda\) and \(\mu\) at the point of intersection as \(\lambda = 3\) and \(\mu = -1\). Thus, the intersection point is \((3, 6, 2)\). 
The distance \(d\) from the point \((7, 8, 9)\) to \((3, 6, 2)\) is: 
\[ d = \sqrt{(7 - 3)^2 + (8 - 6)^2 + (9 - 2)^2} = \sqrt{16 + 4 + 49} = \sqrt{69} \] Therefore, 
\[ d^2 + 6 = 69 + 6 = 75 \]

Was this answer helpful?
1
0
Hide Solution
collegedunia
Verified By Collegedunia

Approach Solution -2

Step 1: Convert the symmetric forms to parametric equations
For the first line \[ \frac{x+6}{3}=\frac{y}{2}=\frac{z+1}{1}=t, \] we get \[ x=-6+3t,\quad y=2t,\quad z=-1+t. \] For the second line \[ \frac{x-7}{4}=\frac{y-9}{3}=\frac{z-4}{2}=s, \] we get \[ x=7+4s,\quad y=9+3s,\quad z=4+2s. \]

Step 2: Find the point of intersection
At the intersection, coordinates must match, so solve \[ -6+3t=7+4s,\quad 2t=9+3s,\quad -1+t=4+2s. \] Solving any two (and checking the third) gives \[ t=3,\quad s=-1. \] Therefore, the intersection point is \[ P=(-6+3\cdot 3,\;2\cdot 3,\;-1+3)=(3,6,2). \]

Step 3: Compute the distance from the given point
Given point \(Q=(7,8,9)\). The displacement vector \( \overrightarrow{PQ} = Q-P = (7-3,\;8-6,\;9-2)=(4,2,7)\).
Hence, \[ d^2=\|\overrightarrow{PQ}\|^2=4^2+2^2+7^2=16+4+49=69. \]

Step 4: Evaluate the required expression
\[ d^2+6=69+6=75. \]

Final answer
75
Was this answer helpful?
0
0