Let awards in event A is 48 and awards in event B is 25 and awards in event C is 18 and also n(A ∪ B ∪ C) = 60, n(A ⋂ B ⋂ C) = 5, then how many got exactly two awards is?
21
25
24
23
The Correct Option is A
Solution and Explanation
The correct answer is option (A) : 21
Number of persons who get exactly 2 awards : n(A)+n(B)+n(C)-n(A\(\cup\)B\(\cup\)C)-2n(A\(\cap\)B\(\cap\)C)
= 48+25+18-60-10
= 21
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Concepts Used:
Sets
In mathematics, a set is a well-defined collection of objects. Sets are named and demonstrated using capital letter. In the set theory, the elements that a set comprises can be any sort of thing: people, numbers, letters of the alphabet, shapes, variables, etc.
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The items existing in a set are commonly known to be either elements or members of a set. The elements of a set are bounded in curly brackets separated by commas.
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The cardinal number, cardinality, or order of a set indicates the total number of elements in the set.
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