We are given the geometry of the trapezium and need to calculate its area.
Step 1: First, determine the coordinates of the vertices of the trapezium using the equation \( y^2 = 4x \).
Step 2: Calculate the length of diagonal AC by using the distance formula between the points.
Step 3: Use the area formula for a trapezium, which involves calculating the parallel sides' lengths and height, to find the area.
Final Conclusion: The area of ABCD is \( \frac{75}{8} \), which is Option 2.
Let $ \mathbb{R} $ denote the set of all real numbers. Then the area of the region $$ \left\{ (x, y) \in \mathbb{R} \times \mathbb{R} : x > 0, y > \frac{1}{x},\ 5x - 4y - 1 > 0,\ 4x + 4y - 17 < 0 \right\} $$ is
Let $ S $ denote the locus of the point of intersection of the pair of lines $$ 4x - 3y = 12\alpha,\quad 4\alpha x + 3\alpha y = 12, $$ where $ \alpha $ varies over the set of non-zero real numbers. Let $ T $ be the tangent to $ S $ passing through the points $ (p, 0) $ and $ (0, q) $, $ q > 0 $, and parallel to the line $ 4x - \frac{3}{\sqrt{2}} y = 0 $.
Then the value of $ pq $ is