We're given matrix A, which is a 3x3 matrix.
The determinant of a 3x3 matrix can be calculated using the following formula:
det(A) = a(ei - fh) - b(di - fg) + c(dh - eg)
Here, a, b, c, d, e, f, g, h, i are the elements of the 3x3 matrix A in the following arrangement:
[ a b c ] [d e f] [g h i ]
We're given the values of matrix A:
A = [2 4 5 0 7 4 3 11 8 ]
Plugging these values into the determinant formula:
det(A) = 2(7 * 8 - 4 * 11) - 4(0 * 8 - 4 * 3) + 5(0 * 11 - 7 * 3)
Calculating the determinant:
det(A) = 2(56 - 44) - 4(0 - 12) + 5(0 - 21) = 2(12) - 4(-12) + 5(-21) = 24 + 48 - 105 = -33
We can see that the determinant of matrix A is -33, which is divisible by 11 (since -33 = 11 * (-3)).
Therefore, the answer is correct, and the determinant of matrix A is indeed divisible by 11.
The correct answer is option (A): det A is divisible by 11
Let α,β be the roots of the equation, ax2+bx+c=0.a,b,c are real and sn=αn+βn and \(\begin{vmatrix}3 &1+s_1 &1+s_2\\1+s_1&1+s_2 &1+s_3\\1+s_2&1+s_3 &1+s_4\end{vmatrix}=\frac{k(a+b+c)^2}{a^4}\) then k=
Read More: Properties of Determinants