Question:

Let \(A=\begin{pmatrix}2&0&3\\4&7&11\\5&4&8\end{pmatrix}\). Then

Updated On: Apr 11, 2025
  • det A is divisible by 11
  • det A is not divisible by 11
  • det A=0
  • A is orthogonal matrix
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The Correct Option is A

Approach Solution - 1

Given Matrix A: 

$A = \begin{bmatrix} 2 & 4 & 5 \\ 0 & 7 & 4 \\ 3 & 11 & 8 \end{bmatrix}$

To find the determinant of a 3x3 matrix, we use:

$\text{det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg)$

Where the matrix is structured as:

$\begin{bmatrix} a & b & c \\ d & e & f \\ g & h & i \end{bmatrix}$

From matrix A, we identify:

  • $a = 2$, $b = 4$, $c = 5$
  • $d = 0$, $e = 7$, $f = 4$
  • $g = 3$, $h = 11$, $i = 8$

Now apply the formula:

$\text{det}(A) = 2(7 \cdot 8 - 4 \cdot 11) - 4(0 \cdot 8 - 4 \cdot 3) + 5(0 \cdot 11 - 7 \cdot 3)$

Step-by-step:

  • $7 \cdot 8 = 56$
  • $4 \cdot 11 = 44$
  • $0 \cdot 8 = 0$
  • $4 \cdot 3 = 12$
  • $0 \cdot 11 = 0$
  • $7 \cdot 3 = 21$

So we get:

$\text{det}(A) = 2(56 - 44) - 4(0 - 12) + 5(0 - 21)$

$= 2(12) - 4(-12) + 5(-21)$

$= 24 + 48 - 105 = -33$

Check divisibility:

$-33$ is divisible by $11$, since $-33 = 11 \cdot (-3)$

Final Answer: Option (A): det A is divisible by 11

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Approach Solution -2

Step 1: Calculate the Determinant of A

The determinant of a 3x3 matrix is calculated as:

\(|A| = a_{11}(a_{22}a_{33} - a_{23}a_{32}) - a_{12}(a_{21}a_{33} - a_{23}a_{31}) + a_{13}(a_{21}a_{32} - a_{22}a_{31})\)

Plugging in the values from matrix A:

\(|A| = 2(7 \cdot 8 - 11 \cdot 4) - 0(4 \cdot 8 - 11 \cdot 5) + 3(4 \cdot 4 - 7 \cdot 5)\)

\(|A| = 2(56 - 44) - 0 + 3(16 - 35)\)

\(|A| = 2(12) + 3(-19) = 24 - 57 = -33\)

Step 2: Check Divisibility by 11

Since \(|A| = -33\), it is divisible by 11 because \(-33 = -3 \cdot 11\).

Step 3: Check if det A = 0

\(|A| = -33 \neq 0\), so det A is not 0.

Step 4: Check if A is an Orthogonal Matrix

For a matrix to be orthogonal, its transpose multiplied by itself must equal the identity matrix, i.e., \(AA^T = I\). In the above case this doesn't hold therefore it isn't orthogonal

\(A^T = \begin{pmatrix} 2 & 4 & 5 \\ 0 & 7 & 4 \\ 3 & 11 & 8 \end{pmatrix}\)

\({A^T} \) This option implies it.

Conclusion:

Since the determinant of A is -33 and is divisible by 11, the correct statement is:

det A is divisible by 11.

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Concepts Used:

Properties of Determinants

Properties of Determinants:

  • Reflection Property: The value of the determinant remains unchanged if its rows and columns are interchanged.
  • Switching Property: The interchanging of any two rows (or columns) of the Determinant changes its signs.
  • All- Zero Property: The Determinants will be equivalent to zero if each term of rows and columns is zero.
  • Proportionality (Repetition) Property: If all elements of a row (or column) are proportional or identical to the elements of some other row (or column), then the determinant is zero.
  • Scalar Multiple Property: If all the elements of a row (or column) of a determinant are multiplied by a non-zero constant, then the determinant gets multiplied by the same constant.
  • Sum Property: If some or all elements of a row or column of a determinant are expressed as sum of two (or more) terms, then the determinant can be expressed as sum of two (or more) determinants.
  • Property of Invariance: If to each element of any row or column of a determinant, the equimultiples of corresponding elements of other row (or column) are added, then value of determinant remains the same, i.e., the value of determinant remain same if we apply the operation Ri → Ri  + kRj or Ci → Ci + kCj
  • Factor Property: If a Determinant Δ becomes 0 while considering the value of x  = α, then (x - α) is considered as a factor of Δ
  • Triangle Property:  If all the elements of a determinant above or below the main diagonal consist of zeros, then the determinant is equal to the product of diagonal elements.

Read More: Properties of Determinants