Step 1. Find the coordinates of \( A \) by solving the lines \( L_1: 3x + 2y = 14 \) and \( L_2: 5x - y = 6 \):
Solving these equations gives \( A(2, 4) \).
Step 2. Find the coordinates of \( B \) by solving the lines \( L_3: 4x + 3y = 8 \) and \( L_4: 6x + y = 5 \):
Solving these equations gives \( B\left(\frac{1}{2}, 2\right) \).
Step 3. Determine the equation of line \( AB \) passing through points \( A(2, 4) \) and \( B\left(\frac{1}{2}, 2\right) \):
The equation of \( AB \) is \( 4x - 3y + 4 = 0 \).
Step 4. Calculate the distance from \( P(5, -2) \) to the line \( AB: 4x - 3y + 4 = 0 \):
\(\text{Distance} = \frac{|4(5) - 3(-2) + 4|}{\sqrt{4^2 + (-3)^2}} = \frac{|20 + 6 + 4|}{\sqrt{16 + 9}} = \frac{30}{5} = 6.\)
So, the distance of point \( P \) from the line \( AB \) is 6.
The Correct Answer is: 6
Draw a rough figure and label suitably in each of the following cases:
(a) Point P lies on AB.
(b) XY s ruu and PQ s ruu intersect at M.
(c) Line l contains E and F but not D.
(d) OP s ruu and OQ s ruu meet at O.