Question:
Let \( A \) be a \( 3 \times 5 \) matrix defined by
\[A = \begin{pmatrix}0 & 1 & 3 & 1 & 2 \\1 & 6 & 2 & 3 & 4 \\1 & 8 & 8 & 5 & 8\end{pmatrix}.\]
Consider the system of linear equations given by
\[A \begin{pmatrix}x_1 \\x_2 \\x_3 \\x_4 \\x_5\end{pmatrix} = \begin{pmatrix}3 \\1 \\10\end{pmatrix},\]
where \( x_1, x_2, x_3, x_4, x_5 \) are real variables. Then
Let \( A \) be a \( 3 \times 5 \) matrix defined by
\[A = \begin{pmatrix}0 & 1 & 3 & 1 & 2 \\1 & 6 & 2 & 3 & 4 \\1 & 8 & 8 & 5 & 8\end{pmatrix}.\]
Consider the system of linear equations given by
\[A \begin{pmatrix}x_1 \\x_2 \\x_3 \\x_4 \\x_5\end{pmatrix} = \begin{pmatrix}3 \\1 \\10\end{pmatrix},\]
where \( x_1, x_2, x_3, x_4, x_5 \) are real variables. Then
\[A = \begin{pmatrix}0 & 1 & 3 & 1 & 2 \\1 & 6 & 2 & 3 & 4 \\1 & 8 & 8 & 5 & 8\end{pmatrix}.\]
Consider the system of linear equations given by
\[A \begin{pmatrix}x_1 \\x_2 \\x_3 \\x_4 \\x_5\end{pmatrix} = \begin{pmatrix}3 \\1 \\10\end{pmatrix},\]
where \( x_1, x_2, x_3, x_4, x_5 \) are real variables. Then
Updated On: Oct 1, 2024
- the rank of π΄ is 2 and the given system has a solution
- the rank of π΄ is 2 and the given system does NOT have a solution
- the rank of π΄ is 3 and the given system has a solution
- the rank of π΄ is 3 and the given system does NOT have a solution
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The Correct Option is B
Solution and Explanation
The correct option is (B): the rank of π΄ is 2 and the given system does NOT have a solution
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