Question:

Let \( A \) and \( B \) be two matrices of suitable orders. Then, which of the following is not correct?

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Transpose of a product follows reverse order: \( (AB)' = B'A' \).
Updated On: Jun 21, 2025
  • \( (A')' = A \)
  • \( (kA)' = kA' \), \( k \) is scalar
  • \( (A' + B')' = A + B \)
  • \( (AB)' = A'B' \)
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The Correct Option is D

Solution and Explanation

We know that: - Transpose of a transpose: \( (A')' = A \)
- Scalar multiple transposes: \( (kA)' = kA' \)
- Addition under transpose: \( (A' + B')' = A + B \)
- But product: \( (AB)' = B'A' \), not \( A'B' \)
So, Option (D) is incorrect.
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