Question:

Let 0ax1000≤a≤x≤100 and f(x)=xa+x100+xa50|x−a|+|x−100|+|x−a−50|.Then the maximum value of f(x) becomes 100 when a is equal to

Updated On: Sep 17, 2024
  • 100
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  • 50
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The Correct Option is A

Solution and Explanation

We're given the function f(x)=xa+x100+xa50f(x)=∣x−a∣+∣x−100∣+∣x−a−50∣ and asked to find the value of a that maximizes f(x). We analyze three
cases for the possible values of x relative to a and a+50.
1. xax≤a: Maximized at x=0.
2. axa+50a≤x≤a+50: Maximized at x=a.
3. xa+50x≥a+50: Maximized at x=100.
Comparing the maximum values in each case, we find that the maximum value of f(x) occurs in Case 1, where 2a+150 is the expression for the
maximum value.
To maximize f(x), we need to maximize 2a+150, which is achieved when a=100.
So, the maximum value of f(x) is 100, and it happens when a is equal to 100. Thus, the correct answer is:100
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