Given reaction sequence:
L → (i) PhMgBr → (ii) H3O+ → M → CrO3/H+ → N → Ph3P=CH2 → Ph2C=CH2
Step-by-step interpretation:
Step 1: L + PhMgBr → M (Grignard reaction)
This is a nucleophilic addition of Grignard reagent (PhMgBr) to a carbonyl compound. For the Grignard reagent to work, L must be a compound with a carbonyl group (like an aldehyde or ketone). If L = Benzaldehyde (Ph-CHO), the reaction proceeds as:
Ph-CHO + PhMgBr → Ph-CH(OH)-Ph (a secondary alcohol, M)
Step 2: M → N using CrO3/H+
This step is oxidation. The alcohol (Ph-CH(OH)-Ph) is oxidized to a ketone:
Ph-CH(OH)-Ph → Ph-CO-Ph (benzophenone, N)
Step 3: N → Final product using Ph3P=CH2 (Wittig reaction)
The ketone (benzophenone) reacts with Ph3P=CH2 to form an alkene:
Ph-CO-Ph + Ph3P=CH2 → Ph2C=CH2
Therefore, the correct identity of L is: Benzaldehyde
Correct option: (A): Benzaldehyde
In organic chemistry, an alkyne is an unsaturated hydrocarbon containing at least one carbon-carbon triple bond. Alkynes are an organic molecule that contains triple bonds between the carbon atoms. Its general formula is CnH2n-2. They are also known as acetylenes. In this article, we will deal with the structure of alkynes.
Alkynes show three types of isomerism