Question:

L.C.M. of \(x^3 - 9x\) and \(x^2 - 2x - 3\) is

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To find the L.C.M. of polynomials, factorize them and take all distinct factors.
Updated On: Apr 25, 2025
  • \(x - 3\)
  • \(x + 3\)
  • \(x(x + 1)\)
  • \(x(x + 3)(x - 3)\)
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The Correct Option is D

Solution and Explanation

We begin by factoring both expressions: \[ x^3 - 9x = x(x^2 - 9) = x(x - 3)(x + 3) \] \[ x^2 - 2x - 3 = (x - 3)(x + 1) \] The L.C.M. is the product of all distinct factors: \[ \text{L.C.M.} = x(x - 3)(x + 3)(x + 1) \] Thus, the correct answer is \(x(x + 3)(x - 3)\).
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