The reduction of \(K_2Cr_2O_7\) by SO2 produces Cr3+ ions, which impart a green colour to the solution.
Sulphur dioxide
Sulphur trioxide
Carbon dioxide
Hydrogen sulphide
When \(K_2Cr_2O_7\) is acidified with dilute \(H_2SO_4 \)and exposed to\( SO_2\), it gets reduced, turning green due to the formation of\( Cr^3+\) ions:
\(Cr_2O ^{2−} _7 + 3SO_2 + 2H ^+ → 2Cr^{3+} + 3SO^{2−}_ 4 + H_2O\).
Given below are two statements :
Statement I : CrO\( _3 \) is a stronger oxidizing agent than MoO\( _3 \)
Statement II : Cr(VI) is more stable than Mo(VI) In the light of the above statements, choose the correct answer from the options given below
Among, Sc, Mn, Co and Cu, identify the element with highest enthalpy of atomisation. The spin only magnetic moment value of that element in its +2 oxidation state is _______BM (in nearest integer).
Let \( S = \left\{ m \in \mathbb{Z} : A^m + A^m = 3I - A^{-6} \right\} \), where
\[ A = \begin{bmatrix} 2 & -1 \\ 1 & 0 \end{bmatrix} \]Then \( n(S) \) is equal to ______.
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to:
The elements, in the columns of the periodic table in which d subshells are being occupied are known as d block elements.
These are the elements that have the capability of forming stable cations with incompletely filled d orbitals. Elements like mercury and Zinc are not considered transition metals because they have electronic configurations: (n-1)d10 ns2. These elements have filled d-orbitals in their ground state and, therefore, even in some of their oxidation states.