To determine the IUPAC name:
1. Identify the longest continuous carbon chain, which has 8 carbons (octane).
2. Number the carbon chain to give the substituents the lowest possible locants: - Methyl groups are at positions 2, 5, and 6.
3. Arrange the substituents in alphabetical order and include their positions.
The compound is named : 2,5,6-Trimethyloctane
The IUPAC name of the following compound is:
Let a line passing through the point $ (4,1,0) $ intersect the line $ L_1: \frac{x - 1}{2} = \frac{y - 2}{3} = \frac{z - 3}{4} $ at the point $ A(\alpha, \beta, \gamma) $ and the line $ L_2: x - 6 = y = -z + 4 $ at the point $ B(a, b, c) $. Then $ \begin{vmatrix} 1 & 0 & 1 \\ \alpha & \beta & \gamma \\ a & b & c \end{vmatrix} \text{ is equal to} $
Resonance in X$_2$Y can be represented as
The enthalpy of formation of X$_2$Y is 80 kJ mol$^{-1}$, and the magnitude of resonance energy of X$_2$Y is: