When chamber is evacuated, the refractive index $(\mu)$ decreases. Therefore, wavelength $\left(\lambda \propto \frac{1}{\mu}\right)$ increases.
Now, fringe width is given by
$ \beta=\frac{\lambda D}{d} $
$\Rightarrow \beta \propto \lambda$
Therefore, as wavelength increases, the fringe width will increase.