Question:

$ \int e^{x} \frac{\left(x-1\right)}{x^{2}} dx $ is equal to

Updated On: Jul 29, 2024
  • $ \frac{e^{x}}{x^{2}} +c $
  • $ \frac{-e^{x}}{x^{2}} +c $
  • $ \frac{e^{x}}{x} +c $
  • $ \frac{-e^{x}}{x} +c $
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The Correct Option is C

Solution and Explanation

$\int e^{x}\left(\frac{x-1}{x^{2}}\right) d x$ $=\int e^{x}\left(\frac{1}{x}-\frac{1}{x^{2}}\right) d x$ $=\frac{e^{x}}{x}+c\left[\because \int e^{x}\left[f(x)+f^{\prime}(x)\right] d x=e^{x} f(x)+c\right]$
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Concepts Used:

Integral

The representation of the area of a region under a curve is called to be as integral. The actual value of an integral can be acquired (approximately) by drawing rectangles.

  • The definite integral of a function can be shown as the area of the region bounded by its graph of the given function between two points in the line.
  • The area of a region is found by splitting it into thin vertical rectangles and applying the lower and the upper limits, the area of the region is summarized.
  • An integral of a function over an interval on which the integral is described.

Also, F(x) is known to be a Newton-Leibnitz integral or antiderivative or primitive of a function f(x) on an interval I.

F'(x) = f(x)

For every value of x = I.

Types of Integrals:

Integral calculus helps to resolve two major types of problems:

  1. The problem of getting a function if its derivative is given.
  2. The problem of getting the area bounded by the graph of a function under given situations.